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How to print size of array parameter in C++?


Example:

#include <iostream> 
using namespace std; 
  
void findSize(int arr[]) 
{ 
    cout << sizeof(arr) << endl; 
} 
  
int main() 
{ 
    int a[10]; 
    cout << sizeof(a) << " "; 
    findSize(a); 
    return 0; 
}

Output:


The above output is for a machine where size of integer is 4 bytes and size of a pointer is 8 bytes.


The cout statement inside main prints 40, and cout in findSize prints 8. The reason is, arrays are always passed pointers in functions, i.e., findSize(int arr[]) and findSize(int *arr) mean exactly same thing. Therefore the cout statement inside findSize() prints size of a pointer.



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