Here we will see Java program for finding square root using the API method.
package test;
import java.util.Scanner;
/**
*
* Java program to find the square root of a number in Java.
* This Java program example demonstrates using Math class
* sqrt() method to get the square root of a number in Java.
*
* @author java67
*/
public class SquareRoot{
public static void main(String args[]) {
//Used to get input number for which square root to find
Scanner scanner = new Scanner(System.in);
System.out.println("Enter number to find square root in Java : ");
//getting input number from user to calculate square root
double square = scanner.nextDouble();
//getting the square root of a number in Java
double squareRoot = Math.sqrt(square);
//printing number and its square root in Java
System.out.printf("Square root of number: %f is : %f %n" , square, squareRoot);
}
}Output:
Enter number to find square root in Java :
64
The square root of a number: 64.000000 is: 8.000000This was our Java program to find the square root of a number in Java. It can find the square root of any floating-point number and you don’t need to only supply integers numbers. As I said use Java standard library methods to calculate square root but prepare with your own version of square root function if going for any programming interview.
Source: Java67
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